#!/usr/bin/env python # -*- coding:utf-8 -*- import re # 1、匹配一篇英文文章的标题 类似 The Voice Of China ''' s = r'(?:[A-Z][a-z]+ ?)+' ret = re.findall(s, 'The Voice Of China Of China') print(ret) ''' # 2、匹配一个网址 # 类似 https://www.baidu.com http://www.cnblogs.com ''' s = r'https?://www\.[A-Za-z]+\.com' ret = re.findall(s, 'https://www.baidu.com http://www.cnblogs.com') print(ret) ''' # 3、匹配年月日日期 类似 2018-12-06 2018/12/06 2018.12.06 ''' s = r'-?\d{1,4}(-|/|\.)((0[1-9])|(1[0-2]))\1((0[1-9])|(1[0-9])|(2[0-9])|(3[0-1]))' ret = re.findall(s, '2018-12-06') print(ret) ''' # 4、匹配15位或者18位身份证号 ''' (\d{6}(19|20)\d\d(0[1-9]|1[0-2])(0[1-9]|1[0-9]|2[0-9]|3[01])\d\d\d(\d|x))+|(\d{8}(0[1-9]|1[0-2])(0[1-9]|1[0-9]|2[0-9]|3[01])\d{3}) ''' # 5、从lianjia.html中匹配出标题，户型和面积，结果如下： # [('金台路交通部部委楼南北大三居带客厅   单位自持物业', '3室1厅', '91.22平米'), ('西山枫林 高楼层南向两居 户型方正 采光好', # '2室1厅', '94.14平米')] ''' import re pattern = '
    
     .*?data-sl="">(?P
     
     /(?P
     
      .*?)' \           '
      /(?P
      
       .*?)
       ' with open(r'D:\homework\day26\1', 'r', encoding='utf-8')as f:     s = f.read()     ret = re.findall(pattern, s, re.S)     print(ret) ''' # 6、1-2*((60-30+(-40/5)*(9-2*5/3+7/3*99/4*2998+10*568/14))-(-4*3)/(16-3*2)) # 从上面算式中匹配出最内层小括号以及小括号内的表达式 ''' \([^()]+\) ''' # 7、从类似9-2*5/3+7/3*99/4*2998+10*568/14的表达式中匹配出乘法或除法 ''' \d+((\*|/)\d+)+ ''' # 8、通读博客，完成三级菜单 # http://www.cnblogs.com/Eva-J/articles/7205734.html ''' menu = {
      '北京': {
          '海淀': {
              '五道口': {
                  'soho': {},                 '网易': {},                 'google': {}             },             '中关村': {
                  '爱奇艺': {},                 '汽车之家': {},                 'youku': {},             },             '上地': {
                  '百度': {},             },         },         '昌平': {
              '沙河': {
                  '老男孩': {},                 '北航': {},             },             '天通苑': {},             '回龙观': {},         },         '朝阳': {},         '东城': {},     },     '上海': {
          '闵行': {
              "人民广场": {
                  '炸鸡店': {}             }         },         '闸北': {
              '火车战': {
                  '携程': {}             }         },         '浦东': {},     },     '山东': {}, } lst = [menu] while True:     for i in lst[-1]:         print(i)     user = input('请选择:')     if user.upper() == 'B':         lst.pop()     elif user.upper() == 'Q':         break     elif lst[-1].get(user):         lst.append(lst[-1][user]) print('已结束') ''' # 9、大作业：计算器 # 1)如何匹配最内层括号内的表达式 ''' \(([^()]+)\) ''' # 2)如何匹配乘除法 ''' \d+((\*|/)\d+)+ ''' # 3)考虑整数和小数 ''' (\d+\.?\d+)|\d+ ''' # 4)写函数，计算‘2*3’,‘10/5’ ''' import re def count(suanshi):     a, b, c = re.split(r'([*/])', suanshi, )     a = int(a)     c = int(c)     if b == '*':         print(a*c)     elif b == '/':         print(a/c) count('10/5') ''' # 5)引用4)中写好的函数，完成'2*3/4'计算 ''' import re def count(suanshi):     try:         while 1:             x = re.search(r'\d+[*/]\d+', suanshi)             a, b, c = re.split(r'([*/])', x.group())             a = int(a)             c = int(c)             if b == '*':                 res = a * c             elif b == '/':                 res = int(a / c)             suanshi = suanshi.replace(x.group(), str(res), 1)             print(suanshi)     except Exception as e:         print('ok') count('2*3*46*3*43*43/43*43/4*53*3') '''